Aménagement hydro-électrique sur la rivière Snake à boeufs Bend, Oregon . b- ned trith la dan appelée sur une échelle de 1 po equalto dix pieds. Salon po2. Vol. de la section Vt.d Sect. Seetion (par planimètre) 1 pi. de large. 1 ft. tide # , (cu.ft) 1-7 84.18 9419. 561 500 18,68 1868 230 2-7, 3-7 00°13,86 9,53 1336 207 900 953 142 950 4-7 5-7 605 6,05 60 750 3,12 46 800 312 C-7 7,93 93 13 950 -10- matériel de la Xhe dan qui est le granit a été assumedto pèsent 150 livres par pied cube. Les forces sho^nin la quatrième colonne représentent les poids du var-reconnaissances articles agissant vers le bas à travers les centres de gra-vity

• Contributeur: The Reading Room / Alamy Banque D'Images
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• Dimensions: 1984 x 1260 px | 33,6 x 21,3 cm | 13,2 x 8,4 inches | 150dpi

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Hydro-electric development on the Snake River at Oxen Bend, Oregon . b- ned trith the dan drawn to a scale of 1 inch equalto ten feet. Area sq. in. Vol. of Sect. Vt.of Sect. Seetion (by planimeter) 1 ft. wide. 1 ft. tide #, (cu.ft) 1-7 84.18 9419. 561, 500 2-7 18.68 1868 230, °00 3-7 13.86 1336 207, 900 4-7 9.53 953 142, 950 5-7 6.05 605 60, 750 C-7 3.12 312 46, 800 7 .93 93 13, 9 50 -10- Xhe material of the dan which is granite was assumedto weigh 150 pounds per cubic foot. The forces sho^nin the fourth column represent the weights of the var-ious sections acting down through the centers of gra-vity of the respective sections. It is now necessaryto obtain the force and the point of application ofthe force due to the ^ater. The center of pressure, Xc, was determined by the equationX = 2 hj - H-, 3 h22 - hiThe force, E, due to the ^ater acting at Xc, wasdetermined by the equation 1J = I bhh^ rr is the reight of one cubic foot of water and isequal to 63.6 , b is the width of the section and <vastaken a.a one foot. The remaining terms are explainedby figure IX.. Fig. II. -11- *a P 61 84, 800 57. 8 76, 100 47.9 56, 700 37.9 36, 700 97 .9 23, 500 17.2 12, 150 7.2 3, 960 The following results were obtained. ^oct. hi ho X h 1-7 14.9 75.3 51.6 44.5 2-7 14.2 71.4 49.1 43.6 3-7 14.2 61.4 42.6 37.6 4-7 14.2 51.4 36.2 32.6 5-7 14.2 41.4 30 27.6 6-7 14.2 31.4 23.8 2^.6 7 14.2 21.4 18.0 17.6 By combining P acting horizontally thru C andtho weight of the dam acting vertically thru the cen-ter of gravity as previously determined, the resultantpressure nay be determined for each section. By con-necting the points where this pressure acts on thetoases of the respective sections, the line of result-ant pressures may be obtained. This line was found tobe very close to the center of the din. It is now necessary to determine the maximumpressure acting on the base of the dan. i— * f e 1 [ J J J 1 1 ii 1 1 1 l sr~ Fig. III. -18» Figure III represents fhe trapezoid of pressure on the base of the dan.

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